WebAug 17, 2024 · Codewars Find Next Perfect Square Solution Explained - Javascript Programming With Arslan 1.63K subscribers Subscribe 1.3K views 1 year ago Find the … WebComplete the findNextSquare method that finds the next integral perfect square after the one passed as a parameter. Recall that an integral perfect square is an integer n such that sqrt (n) is also an integer. If the parameter is itself not a perfect square, than -1 should be returned. You may assume the parameter is positive. Examples:
Codewars Find Next Perfect Square Solution Explained
WebFeb 15, 2024 · Wait! That’s it! You just have to check if your number of building blocks is a perfect square. Task. Given an integral number, determine if it’s a square number: In … WebComplete the findNextSquare method that finds the next integral perfect square after the one passed as a parameter. Recall that an integral perfect square is an integer n such that sqrt (n) is also an integer. If the parameter is itself not a perfect square, than -1 should be returned. You may assume the parameter is positive. mount gravatt mazda used cars
Codewars/Find the odd int.py at master · jlawman/Codewars
WebComplete the findNextSquare method that finds the next integral perfect square after the one passed as a parameter. Recall that an integral perfect square is an integer n such that sqrt(n) is also an integer. If the parameter is itself not a perfect square, than -1 should be returned. You may assume the parameter is positive. Examples: WebAug 27, 2024 · Complete the findNextSquare method that finds the next integral perfect square after the one passed as a parameter. Recall that an integral perfect square is an integer n such that sqrt (n) is also an integer. If the parameter is itself not a perfect square then -1 should be returned. You may assume the parameter is non-negative. WebMar 17, 2016 · from math import sqrt def find_next_square(sq): # Return the next square if sq is a square, -1 otherwise return (sqrt(sq)+1)*(sqrt(sq)+1) if ( (sqrt(sq)+1)*(sqrt(sq)+1)).is_integer() else -1 The Most Precise, And Elegant Solution This one’s by lechevalier: find_next_square=lambda n:-(n**.5%1>0)or(n**.5+1)**2 Here’s … hearth pizzeria mercersburg