Nettet21. mar. 2024 · lim x→∞ sinx x = 0 Explanation: You're going to want to use the squeeze theorem for this. Recall that sinx is only defined on −1 ≤ sinx ≤ 1. Therefore − 1 x ≤ sinx x ≤ 1 x And since lim x→∞ − 1 x = lim x→ ∞ 1 x = 0, then lim x→∞ sinx x = 0. Hopefully this helps! Answer link Nettet3. mar. 2016 · lim x→0 x sinx = 1 Explanation: We can use the squeeze theorem (or sandwich theorem), which states that if g(x) ≤ f (x) ≤ h(x) in an interval around c then lim x→c g(x) ≤ lim x→c f (x) ≤ lim x→c h(x) (providing the limits exist), and that if lim x→c g(x) = l = lim x→c h(x) then lim x→c f (x) = l
求极限解题过程、详细点、、 3x+sinx lim ———— x→0 2x+tanx
Nettet24. sep. 2014 · A simple way to show that this approaches one as x approaches zero is to use the geometric concepts pasmith alluded to earlier. You can show that 1 Nettet6. feb. 2024 · Best answer. lim(θ→0) sinθ/θ = 1. Proof: Consider a circle with centre ‘O’ and radius ‘r’. Mark two point A and B on the circumference of the circle so that (AOB)! … chore system for family
sinxの微分の証明で、lim(h→0)[sin(x+h)-sinx/h]に... - Yahoo!知恵袋
NettetThe correct option is C 0 Explanation for the correct option: Evaluating the limit l i m i t x → ∞ sin x x when we substitute limit it becomes the value sin ∞ ∞ where sin ∞ ∈ - 1, 1 = - 1, 1 ∞ = 0 × - 1, 1 [ ∵ 1 ∞ = 0] = 0 Hence, option (C) is the correct answer Suggest Corrections 0 Similar questions Q. Nettet20. sep. 2007 · sin x < x < tan x (0 Nettet$$\lim_{x \rightarrow 0} \frac {\sin(x)}{x} = 1$$ I know several proofs of this: the geometric proof shows that $\cos(\theta)\leq\frac {\sin(\theta)}{\theta}\leq1$ and using the … chores 意味は