Most difficult sum in the world
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Most difficult sum in the world
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WebGet A Copy. Amazon. Stores . Published (first published September 1987) More Details... Edit Details. Web1 Answer. Sorted by: 10. The trick we use is differentiating under the integral sign. Define. F ( k) = ∫ 0 1 x k − 1 log ( x) d x. Then, ∂ F ( k) ∂ k = ∫ 0 1 x k log ( x) log ( x) d x = ∫ 0 1 x k d x = 1 k + 1. Our original integral can be retrieved by integrating with respect to …
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WebThe sum of π and e is equal to π + e = 3.14159 + 2.71828 = 5.85987. To determine whether this number is algebraic or transcendental, we first need to understand the difference … WebTrigonometry Problems - sin, cos, tan, cot: Very Difficult Problems with Solutions
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